Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a 'desirability' factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).
Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.
Input
* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and DiOutput
* Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints
Sample Input
4 61 42 63 122 7
Sample Output
23 01背包: 直接套模板
#include#include using namespace std;int main(){ int w[35000],v[35000],f[35000]; int n,m,i,j; cin>>n>>m; for(i=0;i >w[i]>>v[i]; for(i=0;i =w[i];j--) f[j]=max(f[j],f[j-w[i]]+v[i]); } cout << f[m] << endl; return 0;}